What are the solutions to the equation x^2= 16/121 ?

The solutions to the equation x^2= 16/121 are x= 4/11 ,x=-4/11

Find the zeros of x^2= 16/121

The zeros of x^2= 16/121 are x= 4/11 ,x=-4/11

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x^{2} = \frac{16}{121}

x = \frac{4}{11}, x = - \frac{4}{11}

Decimal Notation

x = 0.36363 \dots, x = - 0.36363 \dots

Solution steps

x^{2} = \frac{16}{121}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{121}, x = - \frac{16}{121}

\frac{16}{121} = \frac{4}{11}

- \frac{16}{121} = - \frac{4}{11}

x = \frac{4}{11}, x = - \frac{4}{11}

\frac{1}{4} x^{2} + 2 x + 2 = 0

x, x^{2} y + x^{2} - x y^{2} + x y + 2 = 0

(x + 1) (2 x - 5) = 0

- 6 x^{2} - 7 x + 3 = 0

2 x^{2} + 3 x - 1 = 0

What are the solutions to the equation x^2= 16/121 ?
The solutions to the equation x^2= 16/121 are x= 4/11 ,x=-4/11
Find the zeros of x^2= 16/121
The zeros of x^2= 16/121 are x= 4/11 ,x=-4/11