What are the solutions to the equation 2z^2-8=0 ?

The solutions to the equation 2z^2-8=0 are z=2,z=-2

Find the zeros of 2z^2-8=0

The zeros of 2z^2-8=0 are z=2,z=-2

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2 z^{2} - 8 = 0

z = 2, z = - 2

Solution steps

2 z^{2} - 8 = 0

Move

8

to the right side

2 z^{2} = 8

Divide both sides by

2

z^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 4, z = - 4

4 = 2

- 4 = - 2

z = 2, z = - 2

\frac{1}{2} z^{2} + \frac{5}{6} z = 0

2 y^{2} - 8 y - 10 = 0

183000 x^{2} - 1400000 x - 22912000 = 0

24 x^{2} - 3 x - 11 = 0

12 x^{2} - 168 x + 432 = 0

What are the solutions to the equation 2z^2-8=0 ?
The solutions to the equation 2z^2-8=0 are z=2,z=-2
Find the zeros of 2z^2-8=0
The zeros of 2z^2-8=0 are z=2,z=-2