What are the solutions to the equation 2w^2-7w-4=0 ?

The solutions to the equation 2w^2-7w-4=0 are w=4,w=-1/2

Find the zeros of 2w^2-7w-4=0

The zeros of 2w^2-7w-4=0 are w=4,w=-1/2

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2 w^{2} - 7 w - 4 = 0

w = 4, w = - \frac{1}{2}

Decimal Notation

w = 4, w = - 0.5

Solution steps

2 w^{2} - 7 w - 4 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 4) = 9

w_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 2}, w_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 2}

w = \frac{- ( - 7 ) + 9}{2 \cdot 2} : 4

w = \frac{- ( - 7 ) - 9}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

w = 4, w = - \frac{1}{2}

a, c^{2} = a^{2} + a^{2}

2 y^{2} - 4 y + 1 = 0

8.1 \cdot 1 0^{- 12} = (2 x)^{2} \cdot (2.5 \cdot 1 0^{- 3})

Q, p = 6 - 6 Q + 3 Q^{2}

5 z^{2} = 17 z - 14

What are the solutions to the equation 2w^2-7w-4=0 ?
The solutions to the equation 2w^2-7w-4=0 are w=4,w=-1/2
Find the zeros of 2w^2-7w-4=0
The zeros of 2w^2-7w-4=0 are w=4,w=-1/2