What are the solutions to the equation 4x^2-3x=5 ?

The solutions to the equation 4x^2-3x=5 are x=(3+sqrt(89))/8 ,x=(3-sqrt(89))/8

Find the zeros of 4x^2-3x=5

The zeros of 4x^2-3x=5 are x=(3+sqrt(89))/8 ,x=(3-sqrt(89))/8

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4 x^{2} - 3 x = 5

x = \frac{3 + 89}{8}, x = \frac{3 - 89}{8}

Decimal Notation

x = 1.55424 \dots, x = - 0.80424 \dots

Solution steps

4 x^{2} - 3 x = 5

Move

5

to the left side

4 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 5) = 89

x_{1, 2} = \frac{- ( - 3 ) \pm 89}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 89}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 89}{2 \cdot 4}

x = \frac{- ( - 3 ) + 89}{2 \cdot 4} : \frac{3 + 89}{8}

x = \frac{- ( - 3 ) - 89}{2 \cdot 4} : \frac{3 - 89}{8}

The solutions to the quadratic equation are:

x = \frac{3 + 89}{8}, x = \frac{3 - 89}{8}

- 12 w - 9 = 4 w^{2}

4 y - y^{2}

x = 1 (5 - 6 x - 1)^{2}

(k + 2) x^{2} - 5 x + \frac{5}{2} = 0

x, x^{2} + y^{2} - 6 x - 10 y + 34 = 0

What are the solutions to the equation 4x^2-3x=5 ?
The solutions to the equation 4x^2-3x=5 are x=(3+sqrt(89))/8 ,x=(3-sqrt(89))/8
Find the zeros of 4x^2-3x=5
The zeros of 4x^2-3x=5 are x=(3+sqrt(89))/8 ,x=(3-sqrt(89))/8