What are the solutions to the equation a^2-a+2=4 ?

The solutions to the equation a^2-a+2=4 are a=2,a=-1

Find the zeros of a^2-a+2=4

The zeros of a^2-a+2=4 are a=2,a=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} - a + 2 = 4

a = 2, a = - 1

Solution steps

a^{2} - a + 2 = 4

Move

4

to the left side

a^{2} - a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

a_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

a = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

a = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

a = 2, a = - 1

4 x^{2} + 9 = 12 x

x^{2} - \frac{3}{2} x - \frac{3}{4} = 0

x^{2} - 4.16 x + 4.3264 = 0

9 x^{2} - 6 x + (- 4) = 0

(x + 2) (x - 4) = 4 (x - 1)

What are the solutions to the equation a^2-a+2=4 ?
The solutions to the equation a^2-a+2=4 are a=2,a=-1
Find the zeros of a^2-a+2=4
The zeros of a^2-a+2=4 are a=2,a=-1