What are the solutions to the equation (x-2)^2= 1/(4(-2/5)^0) ?

The solutions to the equation (x-2)^2= 1/(4(-2/5)^0) are x= 5/2 ,x= 3/2

Find the zeros of (x-2)^2= 1/(4(-2/5)^0)

The zeros of (x-2)^2= 1/(4(-2/5)^0) are x= 5/2 ,x= 3/2

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(x - 2)^{2} = \frac{1}{4 ( - \frac{2}{5} ) ^{0}}

x = \frac{5}{2}, x = \frac{3}{2}

Decimal Notation

x = 2.5, x = 1.5

Solution steps

(x - 2)^{2} = \frac{1}{4 ( - \frac{2}{5} ) ^{0}}

Simplify

\frac{1}{4 ( - \frac{2}{5} ) ^{0}} : \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = \frac{1}{4} : x = \frac{5}{2}

Solve

x - 2 = - \frac{1}{4} : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{3}{2}

25 x^{2} - 20 x + 5 = 0

x^{2} + (29 - 2 x)^{2} = 1 3^{2}

4 (x - 2)^{2} = x^{2} - 4 x + 7

0.6 x^{2} + 1.4 x - 1.4 = 0

x^{2} - m x + 8 = 0, m, x_{1} = 1

What are the solutions to the equation (x-2)^2= 1/(4(-2/5)^0) ?
The solutions to the equation (x-2)^2= 1/(4(-2/5)^0) are x= 5/2 ,x= 3/2
Find the zeros of (x-2)^2= 1/(4(-2/5)^0)
The zeros of (x-2)^2= 1/(4(-2/5)^0) are x= 5/2 ,x= 3/2