What are the solutions to the equation (x-5)^2=2x-2 ?

The solutions to the equation (x-5)^2=2x-2 are x=9,x=3

Find the zeros of (x-5)^2=2x-2

The zeros of (x-5)^2=2x-2 are x=9,x=3

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(x - 5)^{2} = 2 x - 2

x = 9, x = 3

Solution steps

(x - 5)^{2} = 2 x - 2

Expand

(x - 5)^{2} : x^{2} - 10 x + 25

x^{2} - 10 x + 25 = 2 x - 2

Move

2

to the left side

x^{2} - 10 x + 27 = 2 x

Move

2 x

to the left side

x^{2} - 12 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 27 = 6

x_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6}{2 \cdot 1} : 9

x = \frac{- ( - 12 ) - 6}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 9, x = 3

- x^{2} - 1.8 \cdot 1 0^{- 5} x + 3.336 \cdot 1 0^{- 7} = 0

3 x^{2} + 39 x + 36 = 0

Nt = 0.0054 t^{2} - 1.46 t + 95.11

32 x^{2} - 18 = 0

x, x^{2} + 4 x = 0

What are the solutions to the equation (x-5)^2=2x-2 ?
The solutions to the equation (x-5)^2=2x-2 are x=9,x=3
Find the zeros of (x-5)^2=2x-2
The zeros of (x-5)^2=2x-2 are x=9,x=3