What are the solutions to the equation 2x^2=6-3x ?

The solutions to the equation 2x^2=6-3x are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4

Find the zeros of 2x^2=6-3x

The zeros of 2x^2=6-3x are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4

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2 x^{2} = 6 - 3 x

x = \frac{- 3 + 57}{4}, x = \frac{- 3 - 57}{4}

Decimal Notation

x = 1.13745 \dots, x = - 2.63745 \dots

Solution steps

2 x^{2} = 6 - 3 x

Move

3 x

to the left side

2 x^{2} + 3 x = 6

Move

6

to the left side

2 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 6) = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 \cdot 2}, x_{2} = \frac{- 3 - 57}{2 \cdot 2}

x = \frac{- 3 + 57}{2 \cdot 2} : \frac{- 3 + 57}{4}

x = \frac{- 3 - 57}{2 \cdot 2} : \frac{- 3 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 57}{4}, x = \frac{- 3 - 57}{4}

20 + 10 t - 4.905 t^{2} = 0

4 t - \frac{t ^{2}}{4} = 9.75

6 f^{2} + 6 f - 9 = 0

x^{2} + 10 x - 13 = 17

12 x^{2} - 10 x + 1.5 = 0

What are the solutions to the equation 2x^2=6-3x ?
The solutions to the equation 2x^2=6-3x are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4
Find the zeros of 2x^2=6-3x
The zeros of 2x^2=6-3x are x=(-3+sqrt(57))/4 ,x=(-3-sqrt(57))/4