What are the solutions to the equation solvefor a,a^2+b-c=100 ?

The solutions to the equation solvefor a,a^2+b-c=100 are a=sqrt(100-b+c),a=-sqrt(100-b+c)

Find the zeros of solvefor a,a^2+b-c=100

The zeros of solvefor a,a^2+b-c=100 are a=sqrt(100-b+c),a=-sqrt(100-b+c)

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solve for

a, a^{2} + b - c = 100

a = 100 - b + c, a = - 100 - b + c

Solution steps

a^{2} + b - c = 100

Move

b

to the right side

a^{2} - c = 100 - b

Move

c

to the right side

a^{2} = 100 - b + c

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 100 - b + c, a = - 100 - b + c

(x + 3) (x - 5) = - 8

x^{2} - \frac{3}{2} = 0

x, (5 p - 52) x^{2} - (p - 4) x + 4 = 0

4 x^{2} - 15 x + 10 = 0

x^{2} - 226 x + 1105 = 0

What are the solutions to the equation solvefor a,a^2+b-c=100 ?
The solutions to the equation solvefor a,a^2+b-c=100 are a=sqrt(100-b+c),a=-sqrt(100-b+c)
Find the zeros of solvefor a,a^2+b-c=100
The zeros of solvefor a,a^2+b-c=100 are a=sqrt(100-b+c),a=-sqrt(100-b+c)