What are the solutions to the equation 6w^2-8w+5=0 ?

The solutions to the equation 6w^2-8w+5=0 are w= 2/3+i(sqrt(14))/6 ,w= 2/3-i(sqrt(14))/6

Find the zeros of 6w^2-8w+5=0

The zeros of 6w^2-8w+5=0 are w= 2/3+i(sqrt(14))/6 ,w= 2/3-i(sqrt(14))/6

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6 w^{2} - 8 w + 5 = 0

w = \frac{2}{3} + i \frac{14}{6}, w = \frac{2}{3} - i \frac{14}{6}

Solution steps

6 w^{2} - 8 w + 5 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

Simplify

(- 8)^{2} - 4 \cdot 6 \cdot 5 : 214 i

w_{1, 2} = \frac{- ( - 8 ) \pm 2 14 i}{2 \cdot 6}

Separate the solutions

w_{1} = \frac{- ( - 8 ) + 2 14 i}{2 \cdot 6}, w_{2} = \frac{- ( - 8 ) - 2 14 i}{2 \cdot 6}

w = \frac{- ( - 8 ) + 2 14 i}{2 \cdot 6} : \frac{2}{3} + i \frac{14}{6}

w = \frac{- ( - 8 ) - 2 14 i}{2 \cdot 6} : \frac{2}{3} - i \frac{14}{6}

The solutions to the quadratic equation are:

w = \frac{2}{3} + i \frac{14}{6}, w = \frac{2}{3} - i \frac{14}{6}

x, 4 x y + x^{2} - 3 y^{2} = 2

4 x^{2} - 72 = 0

(- \frac{1}{3})^{2} + y^{2} = 1

- 4.9 t^{2} + 73.92 = \frac{1}{2} \cdot 73.92

z^{2} + 6 z + 10

What are the solutions to the equation 6w^2-8w+5=0 ?
The solutions to the equation 6w^2-8w+5=0 are w= 2/3+i(sqrt(14))/6 ,w= 2/3-i(sqrt(14))/6
Find the zeros of 6w^2-8w+5=0
The zeros of 6w^2-8w+5=0 are w= 2/3+i(sqrt(14))/6 ,w= 2/3-i(sqrt(14))/6