What are the solutions to the equation (-x+4)^2=40 ?

The solutions to the equation (-x+4)^2=40 are x=-2sqrt(10)+4,x=2sqrt(10)+4

Find the zeros of (-x+4)^2=40

The zeros of (-x+4)^2=40 are x=-2sqrt(10)+4,x=2sqrt(10)+4

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(- x + 4)^{2} = 40

x = - 210 + 4, x = 210 + 4

Decimal Notation

x = - 2.32455 \dots, x = 10.32455 \dots

Solution steps

(- x + 4)^{2} = 40

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- x + 4 = 40 : x = - 210 + 4

Solve

- x + 4 = - 40 : x = 210 + 4

The solutions to the quadratic equation are:

x = - 210 + 4, x = 210 + 4

0.00029 = \frac{4 π \cdot 1 0 ^{- 7} \cdot x ^{2} \cdot 12.25}{4}

\frac{x ^{2}}{4} = 83

1 4^{2} = x^{2} + x^{2}

3 x^{2} - 12 x + 11

3 x^{2} - 12 x + 15

What are the solutions to the equation (-x+4)^2=40 ?
The solutions to the equation (-x+4)^2=40 are x=-2sqrt(10)+4,x=2sqrt(10)+4
Find the zeros of (-x+4)^2=40
The zeros of (-x+4)^2=40 are x=-2sqrt(10)+4,x=2sqrt(10)+4