What are the solutions to the equation 15x^2+22x=-8 ?

The solutions to the equation 15x^2+22x=-8 are x=-2/3 ,x=-4/5

Find the zeros of 15x^2+22x=-8

The zeros of 15x^2+22x=-8 are x=-2/3 ,x=-4/5

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15 x^{2} + 22 x = - 8

x = - \frac{2}{3}, x = - \frac{4}{5}

Decimal Notation

x = - 0.66666 \dots, x = - 0.8

Solution steps

15 x^{2} + 22 x = - 8

Move

8

to the left side

15 x^{2} + 22 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 15 \cdot 8}{2 \cdot 15}

2 2^{2} - 4 \cdot 15 \cdot 8 = 2

x_{1, 2} = \frac{- 22 \pm 2}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 22 + 2}{2 \cdot 15}, x_{2} = \frac{- 22 - 2}{2 \cdot 15}

x = \frac{- 22 + 2}{2 \cdot 15} : - \frac{2}{3}

x = \frac{- 22 - 2}{2 \cdot 15} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - \frac{4}{5}

\frac{4 x + 5}{2} = - 3

\frac{a}{a ^{2}}

(1 + 4 i)^{2}

\frac{1 + 2}{1 - 2}

x (x + 3) > 0

What are the solutions to the equation 15x^2+22x=-8 ?
The solutions to the equation 15x^2+22x=-8 are x=-2/3 ,x=-4/5
Find the zeros of 15x^2+22x=-8
The zeros of 15x^2+22x=-8 are x=-2/3 ,x=-4/5