What are the solutions to the equation r^2+10r+24=0 ?

The solutions to the equation r^2+10r+24=0 are r=-4,r=-6

Find the zeros of r^2+10r+24=0

The zeros of r^2+10r+24=0 are r=-4,r=-6

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r^{2} + 10 r + 24 = 0

r = - 4, r = - 6

Solution steps

r^{2} + 10 r + 24 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

r_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 10 + 2}{2 \cdot 1}, r_{2} = \frac{- 10 - 2}{2 \cdot 1}

r = \frac{- 10 + 2}{2 \cdot 1} : - 4

r = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

r = - 4, r = - 6

(7 x - 5) (x - 2) = 0

x, (x - 3) (x + 4) = 18

(5 - x)^{2} + 3 = 0

x^{2} + 30 x - 2 = 0

16 x^{2} = - 9

What are the solutions to the equation r^2+10r+24=0 ?
The solutions to the equation r^2+10r+24=0 are r=-4,r=-6
Find the zeros of r^2+10r+24=0
The zeros of r^2+10r+24=0 are r=-4,r=-6