What are the solutions to the equation x^2-16/3 x+2=0 ?

The solutions to the equation x^2-16/3 x+2=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3

Find the zeros of x^2-16/3 x+2=0

The zeros of x^2-16/3 x+2=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3

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x^{2} - \frac{16}{3} x + 2 = 0

x = \frac{8 + 46}{3}, x = \frac{8 - 46}{3}

Decimal Notation

x = 4.92744 \dots, x = 0.40589 \dots

Solution steps

x^{2} - \frac{16}{3} x + 2 = 0

Multiply both sides by

3

3 x^{2} - 16 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 6 = 246

x_{1, 2} = \frac{- ( - 16 ) \pm 2 46}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 46}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 2 46}{2 \cdot 3}

x = \frac{- ( - 16 ) + 2 46}{2 \cdot 3} : \frac{8 + 46}{3}

x = \frac{- ( - 16 ) - 2 46}{2 \cdot 3} : \frac{8 - 46}{3}

The solutions to the quadratic equation are:

x = \frac{8 + 46}{3}, x = \frac{8 - 46}{3}

x^{2} + 7 x - 250 = 0

(2 x - 1) (4 x + 3) = (2 x - 1) (x - 2)

5 4^{2} + b^{2} = 9 0^{2}

9 X^{2} - 36 = 0

- 45 x^{2} + 0.6 x - 0.002 = 0

What are the solutions to the equation x^2-16/3 x+2=0 ?
The solutions to the equation x^2-16/3 x+2=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3
Find the zeros of x^2-16/3 x+2=0
The zeros of x^2-16/3 x+2=0 are x=(8+sqrt(46))/3 ,x=(8-sqrt(46))/3