What are the solutions to the equation 460=x^2+3x ?

The solutions to the equation 460=x^2+3x are x=20,x=-23

Find the zeros of 460=x^2+3x

The zeros of 460=x^2+3x are x=20,x=-23

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460 = x^{2} + 3 x

x = 20, x = - 23

Solution steps

460 = x^{2} + 3 x

Switch sides

x^{2} + 3 x = 460

Move

460

to the left side

x^{2} + 3 x - 460 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 460 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 460) = 43

x_{1, 2} = \frac{- 3 \pm 43}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 43}{2 \cdot 1}, x_{2} = \frac{- 3 - 43}{2 \cdot 1}

x = \frac{- 3 + 43}{2 \cdot 1} : 20

x = \frac{- 3 - 43}{2 \cdot 1} : - 23

The solutions to the quadratic equation are:

x = 20, x = - 23

(t^{2} D^{2} - t D) = 0

6 x^{2} - 12 x - 2 = 0

- 4 x^{2} - 16 = 0

10 x^{2} + 15 x + 4 = 0

x, y = (x + 4)^{2}

What are the solutions to the equation 460=x^2+3x ?
The solutions to the equation 460=x^2+3x are x=20,x=-23
Find the zeros of 460=x^2+3x
The zeros of 460=x^2+3x are x=20,x=-23