What are the solutions to the equation (5x-3)(2x+7)=0 ?

The solutions to the equation (5x-3)(2x+7)=0 are x= 3/5 ,x=-7/2

Find the zeros of (5x-3)(2x+7)=0

The zeros of (5x-3)(2x+7)=0 are x= 3/5 ,x=-7/2

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(5 x - 3) (2 x + 7) = 0

x = \frac{3}{5}, x = - \frac{7}{2}

Decimal Notation

x = 0.6, x = - 3.5

Solution steps

(5 x - 3) (2 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 3 = 0 or 2 x + 7 = 0

Solve

5 x - 3 = 0 : x = \frac{3}{5}

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - \frac{7}{2}

y, 2 y^{2} + 2 (0.5) y - 1 = 0

(2 x - 4) 3 x = 0

x^{2} + x - n = 0

x^{2} + 4 + 1 = 0

p^{2} - 12 p + 32 = 0

What are the solutions to the equation (5x-3)(2x+7)=0 ?
The solutions to the equation (5x-3)(2x+7)=0 are x= 3/5 ,x=-7/2
Find the zeros of (5x-3)(2x+7)=0
The zeros of (5x-3)(2x+7)=0 are x= 3/5 ,x=-7/2