What are the solutions to the equation 6^4=(5x-9)^2 ?

The solutions to the equation 6^4=(5x-9)^2 are x=9,x=-27/5

Find the zeros of 6^4=(5x-9)^2

The zeros of 6^4=(5x-9)^2 are x=9,x=-27/5

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6^{4} = (5 x - 9)^{2}

x = 9, x = - \frac{27}{5}

Decimal Notation

x = 9, x = - 5.4

Solution steps

6^{4} = (5 x - 9)^{2}

Switch sides

(5 x - 9)^{2} = 6^{4}

6^{4} = 1296

(5 x - 9)^{2} = 1296

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 9 = 1296 : x = 9

Solve

5 x - 9 = - 1296 : x = - \frac{27}{5}

The solutions to the quadratic equation are:

x = 9, x = - \frac{27}{5}

120 = - 5 t^{2} + 40 t + 40

- w^{2} + 5 w - 4 = 0

x = 16 - 0.0003 (x - 3)^{2} 2200

x, f (x + 3) = x^{2} + 3

3 (x^{2} - 4 x + 4) = 0

What are the solutions to the equation 6^4=(5x-9)^2 ?
The solutions to the equation 6^4=(5x-9)^2 are x=9,x=-27/5
Find the zeros of 6^4=(5x-9)^2
The zeros of 6^4=(5x-9)^2 are x=9,x=-27/5