What are the solutions to the equation 3m^2-17m-28=0 ?

The solutions to the equation 3m^2-17m-28=0 are m=7,m=-4/3

Find the zeros of 3m^2-17m-28=0

The zeros of 3m^2-17m-28=0 are m=7,m=-4/3

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3 m^{2} - 17 m - 28 = 0

m = 7, m = - \frac{4}{3}

Decimal Notation

m = 7, m = - 1.33333 \dots

Solution steps

3 m^{2} - 17 m - 28 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 3 ( - 28 )}{2 \cdot 3}

(- 17)^{2} - 4 \cdot 3 (- 28) = 25

m_{1, 2} = \frac{- ( - 17 ) \pm 25}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 17 ) + 25}{2 \cdot 3}, m_{2} = \frac{- ( - 17 ) - 25}{2 \cdot 3}

m = \frac{- ( - 17 ) + 25}{2 \cdot 3} : 7

m = \frac{- ( - 17 ) - 25}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

m = 7, m = - \frac{4}{3}

5 r^{2} - 44 r + 120 = - 30 + 11 r

x^{2} - 10 x + 3

0 = x^{2} + 8 x - 20

- 8 x^{2} + 80 = 0

(x - 2)^{2} - 11 = 14

What are the solutions to the equation 3m^2-17m-28=0 ?
The solutions to the equation 3m^2-17m-28=0 are m=7,m=-4/3
Find the zeros of 3m^2-17m-28=0
The zeros of 3m^2-17m-28=0 are m=7,m=-4/3