What are the solutions to the equation 2y^{(2)}-9y+1=0 ?

The solutions to the equation 2y^{(2)}-9y+1=0 are y=(9+sqrt(73))/4 ,y=(9-sqrt(73))/4

Find the zeros of 2y^{(2)}-9y+1=0

The zeros of 2y^{(2)}-9y+1=0 are y=(9+sqrt(73))/4 ,y=(9-sqrt(73))/4

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2 y^{(2)} - 9 y + 1 = 0

y = \frac{9 + 73}{4}, y = \frac{9 - 73}{4}

Decimal Notation

y = 4.38600 \dots, y = 0.11399 \dots

Solution steps

2 y^{(2)} - 9 y + 1 = 0

Refine

2 y^{2} - 9 y + 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 1 = 73

y_{1, 2} = \frac{- ( - 9 ) \pm 73}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 73}{2 \cdot 2}, y_{2} = \frac{- ( - 9 ) - 73}{2 \cdot 2}

y = \frac{- ( - 9 ) + 73}{2 \cdot 2} : \frac{9 + 73}{4}

y = \frac{- ( - 9 ) - 73}{2 \cdot 2} : \frac{9 - 73}{4}

The solutions to the quadratic equation are:

y = \frac{9 + 73}{4}, y = \frac{9 - 73}{4}

8.5076 x^{2} + (- 452.881) x + 4293.054 = 0

4 a^{2} - 10 a - 24 = 0

x^{2} - 7 x = 0

x^{2} + 60 x - 700 = 0

0 = - x^{2} - 2 x + 47

What are the solutions to the equation 2y^{(2)}-9y+1=0 ?
The solutions to the equation 2y^{(2)}-9y+1=0 are y=(9+sqrt(73))/4 ,y=(9-sqrt(73))/4
Find the zeros of 2y^{(2)}-9y+1=0
The zeros of 2y^{(2)}-9y+1=0 are y=(9+sqrt(73))/4 ,y=(9-sqrt(73))/4