What are the solutions to the equation x^2+3x+x=0 ?

The solutions to the equation x^2+3x+x=0 are x=0,x=-4

Find the zeros of x^2+3x+x=0

The zeros of x^2+3x+x=0 are x=0,x=-4

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x^{2} + 3 x + x = 0

x = 0, x = - 4

Solution steps

x^{2} + 3 x + x = 0

Refine

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

x, x^{2} y + 2 y = x + 4

\frac{3 x ^{2}}{4} = \frac{x}{5} + 2

a, (a + b + c) (1 + ab + a c + b c) = 32

8 x^{2} - 10 x + 7 = 2

5 x^{2} + 6 x = 8

What are the solutions to the equation x^2+3x+x=0 ?
The solutions to the equation x^2+3x+x=0 are x=0,x=-4
Find the zeros of x^2+3x+x=0
The zeros of x^2+3x+x=0 are x=0,x=-4