What are the solutions to the equation 16^2+b^2=20^2 ?

The solutions to the equation 16^2+b^2=20^2 are b=12,b=-12

Find the zeros of 16^2+b^2=20^2

The zeros of 16^2+b^2=20^2 are b=12,b=-12

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1 6^{2} + b^{2} = 2 0^{2}

b = 12, b = - 12

Solution steps

1 6^{2} + b^{2} = 2 0^{2}

Move

1 6^{2}

to the right side

b^{2} = 144

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 144, b = - 144

144 = 12

- 144 = - 12

b = 12, b = - 12

3 (3 x - 2) = (x + 4) \cdot (4 - x)

9 x^{2} + 10 = 5

6 x - 7 x^{2} + 6 = 0

2 x^{2} + 2 x - 1 = 4 x - 2

x, ln (y) = \frac{x ^{2}}{2}

What are the solutions to the equation 16^2+b^2=20^2 ?
The solutions to the equation 16^2+b^2=20^2 are b=12,b=-12
Find the zeros of 16^2+b^2=20^2
The zeros of 16^2+b^2=20^2 are b=12,b=-12