What are the solutions to the equation x^2-7x+n=0 ?

The solutions to the equation x^2-7x+n=0 are x=(7+sqrt(49-4n))/2 ,x=(7-sqrt(49-4n))/2

Find the zeros of x^2-7x+n=0

The zeros of x^2-7x+n=0 are x=(7+sqrt(49-4n))/2 ,x=(7-sqrt(49-4n))/2

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x^{2} - 7 x + n = 0

x = \frac{7 + 49 - 4 n}{2}, x = \frac{7 - 49 - 4 n}{2}

Solution steps

x^{2} - 7 x + n = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot n}{2 \cdot 1}

Simplify

(- 7)^{2} - 4 \cdot 1 \cdot n : 49 - 4 n

x_{1, 2} = \frac{- ( - 7 ) \pm 49 - 4 n}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 49 - 4 n}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 49 - 4 n}{2 \cdot 1}

x = \frac{- ( - 7 ) + 49 - 4 n}{2 \cdot 1} : \frac{7 + 49 - 4 n}{2}

x = \frac{- ( - 7 ) - 49 - 4 n}{2 \cdot 1} : \frac{7 - 49 - 4 n}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 49 - 4 n}{2}, x = \frac{7 - 49 - 4 n}{2}

- 0.1 x^{2} - x + 60 = 0.2 x^{2} + 3 x + 20

20 = 4 + 33 t - 16 t^{2}

4 x^{2} + 8 x = 12

(k - 1)^{2} = 0

4 x^{2} - 5 x = 9

What are the solutions to the equation x^2-7x+n=0 ?
The solutions to the equation x^2-7x+n=0 are x=(7+sqrt(49-4n))/2 ,x=(7-sqrt(49-4n))/2
Find the zeros of x^2-7x+n=0
The zeros of x^2-7x+n=0 are x=(7+sqrt(49-4n))/2 ,x=(7-sqrt(49-4n))/2