What are the solutions to the equation x^2-16x+49=0 ?

The solutions to the equation x^2-16x+49=0 are x=8+sqrt(15),x=8-sqrt(15)

Find the zeros of x^2-16x+49=0

The zeros of x^2-16x+49=0 are x=8+sqrt(15),x=8-sqrt(15)

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x^{2} - 16 x + 49 = 0

x = 8 + 15, x = 8 - 15

Decimal Notation

x = 11.87298 \dots, x = 4.12701 \dots

Solution steps

x^{2} - 16 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 49 = 215

x_{1, 2} = \frac{- ( - 16 ) \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 15}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 15}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 15}{2 \cdot 1} : 8 + 15

x = \frac{- ( - 16 ) - 2 15}{2 \cdot 1} : 8 - 15

The solutions to the quadratic equation are:

x = 8 + 15, x = 8 - 15

3 x + 6 y

49 \cdot 2

1 \leq ∣ x ∣ < 4

x^{2} - 3 x + 9 \leq 0

7^{2} + 7^{2} = c^{2}

What are the solutions to the equation x^2-16x+49=0 ?
The solutions to the equation x^2-16x+49=0 are x=8+sqrt(15),x=8-sqrt(15)
Find the zeros of x^2-16x+49=0
The zeros of x^2-16x+49=0 are x=8+sqrt(15),x=8-sqrt(15)