What are the solutions to the equation completesquare 2x^2-3x+1=0 ?

The solutions to the equation completesquare 2x^2-3x+1=0 are x=1,x= 1/2

Find the zeros of completesquare 2x^2-3x+1=0

The zeros of completesquare 2x^2-3x+1=0 are x=1,x= 1/2

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2 x^{2} - 3 x + 1 = 0

x = 1, x = \frac{1}{2}

Decimal Notation

x = 1, x = 0.5

Solution steps

2 x^{2} - 3 x + 1 = 0

Move

1

to the right side

2 x^{2} - 3 x = - 1

Divide both sides by

2

\frac{2 x ^{2} - 3 x}{2} = \frac{- 1}{2}

x^{2} - \frac{3 x}{2} = - \frac{1}{2}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{3}{4})^{2} = \frac{1}{16}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{3}{4} = \frac{1}{16} : x = 1

Solve

x - \frac{3}{4} = - \frac{1}{16} : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{2}

4 k^{2} + 3 = - 13 k

y, c y^{2} = x^{2} (x - a)

x^{2} - 13 x - 300 = 0

x^{2} - 55 x = 56

x, f (x + h) = 2 (x + h)^{2} + 5 (x + h) - 3

What are the solutions to the equation completesquare 2x^2-3x+1=0 ?
The solutions to the equation completesquare 2x^2-3x+1=0 are x=1,x= 1/2
Find the zeros of completesquare 2x^2-3x+1=0
The zeros of completesquare 2x^2-3x+1=0 are x=1,x= 1/2