What are the solutions to the equation 4=6x+x^2 ?

The solutions to the equation 4=6x+x^2 are x=-3+sqrt(13),x=-3-sqrt(13)

Find the zeros of 4=6x+x^2

The zeros of 4=6x+x^2 are x=-3+sqrt(13),x=-3-sqrt(13)

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4 = 6 x + x^{2}

x = - 3 + 13, x = - 3 - 13

Decimal Notation

x = 0.60555 \dots, x = - 6.60555 \dots

Solution steps

4 = 6 x + x^{2}

Switch sides

6 x + x^{2} = 4

Move

4

to the left side

6 x + x^{2} - 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 4) = 213

x_{1, 2} = \frac{- 6 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 13}{2 \cdot 1}

x = \frac{- 6 + 2 13}{2 \cdot 1} : - 3 + 13

x = \frac{- 6 - 2 13}{2 \cdot 1} : - 3 - 13

The solutions to the quadratic equation are:

x = - 3 + 13, x = - 3 - 13

(x - 3.5)^{2} + (0.268 x - 0.402)^{2} = 4

0 = 6 x^{2} + 18 x

- x^{2} + 12 x - 32

9 w^{2} + 25 = - 30 w

2 z^{2} - z - 1 = 0

What are the solutions to the equation 4=6x+x^2 ?
The solutions to the equation 4=6x+x^2 are x=-3+sqrt(13),x=-3-sqrt(13)
Find the zeros of 4=6x+x^2
The zeros of 4=6x+x^2 are x=-3+sqrt(13),x=-3-sqrt(13)