What are the solutions to the equation solvefor x,3x^2-6y^2+3xy+x+2y=0 ?

The solutions to the equation solvefor x,3x^2-6y^2+3xy+x+2y=0 are x=(3y-1)/3 ,x=-2y

Find the zeros of solvefor x,3x^2-6y^2+3xy+x+2y=0

The zeros of solvefor x,3x^2-6y^2+3xy+x+2y=0 are x=(3y-1)/3 ,x=-2y

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solve for

x, 3 x^{2} - 6 y^{2} + 3 x y + x + 2 y = 0

x = \frac{3 y - 1}{3}, x = - 2 y

Solution steps

3 x^{2} - 6 y^{2} + 3 x y + x + 2 y = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + (3 y + 1) x - 6 y^{2} + 2 y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 3 y + 1 ) \pm ( 3 y + 1 ) ^{2} - 4 \cdot 3 ( - 6 y ^{2} + 2 y )}{2 \cdot 3}

Simplify

(3 y + 1)^{2} - 4 \cdot 3 (- 6 y^{2} + 2 y) : 9 y - 1

x_{1, 2} = \frac{- ( 3 y + 1 ) \pm ( 9 y - 1 )}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( 3 y + 1 ) + 9 y - 1}{2 \cdot 3}, x_{2} = \frac{- ( 3 y + 1 ) - ( 9 y - 1 )}{2 \cdot 3}

x = \frac{- ( 3 y + 1 ) + 9 y - 1}{2 \cdot 3} : \frac{3 y - 1}{3}

x = \frac{- ( 3 y + 1 ) - ( 9 y - 1 )}{2 \cdot 3} : - 2 y

The solutions to the quadratic equation are:

x = \frac{3 y - 1}{3}, x = - 2 y

h^{2} + 8 0^{2} = (2 h + 11)^{2}

2 x^{(2)} - 9 x - 18 = 0

x^{2} + 9 x + 8 = 0

3 α^{2} = 147

2 (x - 1) = 3 x (x - 1) - 2 x

What are the solutions to the equation solvefor x,3x^2-6y^2+3xy+x+2y=0 ?
The solutions to the equation solvefor x,3x^2-6y^2+3xy+x+2y=0 are x=(3y-1)/3 ,x=-2y
Find the zeros of solvefor x,3x^2-6y^2+3xy+x+2y=0
The zeros of solvefor x,3x^2-6y^2+3xy+x+2y=0 are x=(3y-1)/3 ,x=-2y