What are the solutions to the equation -7x^2+x+6=0 ?

The solutions to the equation -7x^2+x+6=0 are x=-6/7 ,x=1

Find the zeros of -7x^2+x+6=0

The zeros of -7x^2+x+6=0 are x=-6/7 ,x=1

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- 7 x^{2} + x + 6 = 0

x = - \frac{6}{7}, x = 1

Decimal Notation

x = - 0.85714 \dots, x = 1

Solution steps

- 7 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 7 ) \cdot 6}{2 ( - 7 )}

1^{2} - 4 (- 7) \cdot 6 = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 ( - 7 )}, x_{2} = \frac{- 1 - 13}{2 ( - 7 )}

x = \frac{- 1 + 13}{2 ( - 7 )} : - \frac{6}{7}

x = \frac{- 1 - 13}{2 ( - 7 )} : 1

The solutions to the quadratic equation are:

x = - \frac{6}{7}, x = 1

s^{2} + 100 = 0

12 x^{2} - 6 x + 5

x (x + 10) = - 34

x, a x^{2} + b x + c = o

lo g_{10} (3) (x^{2} - 6) - lo g_{10} (3) (x + 6) = 0

What are the solutions to the equation -7x^2+x+6=0 ?
The solutions to the equation -7x^2+x+6=0 are x=-6/7 ,x=1
Find the zeros of -7x^2+x+6=0
The zeros of -7x^2+x+6=0 are x=-6/7 ,x=1