What are the solutions to the equation x^2+(1+sqrt(2))x+sqrt(2)=0 ?

The solutions to the equation x^2+(1+sqrt(2))x+sqrt(2)=0 are x=-1,x=-sqrt(2)

Find the zeros of x^2+(1+sqrt(2))x+sqrt(2)=0

The zeros of x^2+(1+sqrt(2))x+sqrt(2)=0 are x=-1,x=-sqrt(2)

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x^{2} + (1 + 2) x + 2 = 0

x = - 1, x = - 2

Decimal Notation

x = - 1, x = - 1.41421 \dots

Solution steps

x^{2} + (1 + 2) x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 1 + 2 ) \pm ( 1 + 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(1 + 2)^{2} - 4 \cdot 1 \cdot 2 = 2 - 1

x_{1, 2} = \frac{- ( 1 + 2 ) \pm ( 2 - 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( 1 + 2 ) + 2 - 1}{2 \cdot 1}, x_{2} = \frac{- ( 1 + 2 ) - ( 2 - 1 )}{2 \cdot 1}

x = \frac{- ( 1 + 2 ) + 2 - 1}{2 \cdot 1} : - 1

x = \frac{- ( 1 + 2 ) - ( 2 - 1 )}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

- 4 x^{2} - 5 x - 3 = 0

X^{2} - 2 X - 2 = 0

x^{2} - 2 x + 1 = - 4 x + 9

3 k^{2} - k - 3 = 0

30 y = 9 y^{2} + 25

What are the solutions to the equation x^2+(1+sqrt(2))x+sqrt(2)=0 ?
The solutions to the equation x^2+(1+sqrt(2))x+sqrt(2)=0 are x=-1,x=-sqrt(2)
Find the zeros of x^2+(1+sqrt(2))x+sqrt(2)=0
The zeros of x^2+(1+sqrt(2))x+sqrt(2)=0 are x=-1,x=-sqrt(2)