What are the solutions to the equation 6x^2-2x=3 ?

The solutions to the equation 6x^2-2x=3 are x=(1+sqrt(19))/6 ,x=(1-sqrt(19))/6

Find the zeros of 6x^2-2x=3

The zeros of 6x^2-2x=3 are x=(1+sqrt(19))/6 ,x=(1-sqrt(19))/6

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6 x^{2} - 2 x = 3

x = \frac{1 + 19}{6}, x = \frac{1 - 19}{6}

Decimal Notation

x = 0.89314 \dots, x = - 0.55981 \dots

Solution steps

6 x^{2} - 2 x = 3

Move

3

to the left side

6 x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 2)^{2} - 4 \cdot 6 (- 3) = 219

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19}{2 \cdot 6}, x_{2} = \frac{- ( - 2 ) - 2 19}{2 \cdot 6}

x = \frac{- ( - 2 ) + 2 19}{2 \cdot 6} : \frac{1 + 19}{6}

x = \frac{- ( - 2 ) - 2 19}{2 \cdot 6} : \frac{1 - 19}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 19}{6}, x = \frac{1 - 19}{6}

x + 2 = - x^{2} + 4 x + 2

x^{2} + 25 = 36

2 (x - 1)^{2} = - 16

6 x^{2} - 194 x + 120 = 0

25 x^{2} + 1 = 6 x

What are the solutions to the equation 6x^2-2x=3 ?
The solutions to the equation 6x^2-2x=3 are x=(1+sqrt(19))/6 ,x=(1-sqrt(19))/6
Find the zeros of 6x^2-2x=3
The zeros of 6x^2-2x=3 are x=(1+sqrt(19))/6 ,x=(1-sqrt(19))/6