What are the solutions to the equation 15p^2-3p=0 ?

The solutions to the equation 15p^2-3p=0 are p= 1/5 ,p=0

Find the zeros of 15p^2-3p=0

The zeros of 15p^2-3p=0 are p= 1/5 ,p=0

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15 p^{2} - 3 p = 0

p = \frac{1}{5}, p = 0

Decimal Notation

p = 0.2, p = 0

Solution steps

15 p^{2} - 3 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 15 \cdot 0}{2 \cdot 15}

(- 3)^{2} - 4 \cdot 15 \cdot 0 = 3

p_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 15}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 15}, p_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 15}

p = \frac{- ( - 3 ) + 3}{2 \cdot 15} : \frac{1}{5}

p = \frac{- ( - 3 ) - 3}{2 \cdot 15} : 0

The solutions to the quadratic equation are:

p = \frac{1}{5}, p = 0

x^{2} - 20 x + 25 = 0

x, 1 - 2 x - x^{2} cos (y) = 0

\frac{1}{2} x \frac{3}{2} (x + 1) - \frac{1}{4} = 5

9 z^{2} = 36

121 x^{2} - 4 = 0

What are the solutions to the equation 15p^2-3p=0 ?
The solutions to the equation 15p^2-3p=0 are p= 1/5 ,p=0
Find the zeros of 15p^2-3p=0
The zeros of 15p^2-3p=0 are p= 1/5 ,p=0