What are the solutions to the equation 8x^2-22x+5=0 ?

The solutions to the equation 8x^2-22x+5=0 are x= 5/2 ,x= 1/4

Find the zeros of 8x^2-22x+5=0

The zeros of 8x^2-22x+5=0 are x= 5/2 ,x= 1/4

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8 x^{2} - 22 x + 5 = 0

x = \frac{5}{2}, x = \frac{1}{4}

Decimal Notation

x = 2.5, x = 0.25

Solution steps

8 x^{2} - 22 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 8 \cdot 5}{2 \cdot 8}

(- 22)^{2} - 4 \cdot 8 \cdot 5 = 18

x_{1, 2} = \frac{- ( - 22 ) \pm 18}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 18}{2 \cdot 8}, x_{2} = \frac{- ( - 22 ) - 18}{2 \cdot 8}

x = \frac{- ( - 22 ) + 18}{2 \cdot 8} : \frac{5}{2}

x = \frac{- ( - 22 ) - 18}{2 \cdot 8} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{4}

x, x^{2} + 6 x - 3 = 0

3 x^{2} - 9 x + 4 = 0

4 y^{2} = 36

(x - 2)^{2} = - 13

30.33 = - 4.9 t^{2} + 21.9 t + 36.2

What are the solutions to the equation 8x^2-22x+5=0 ?
The solutions to the equation 8x^2-22x+5=0 are x= 5/2 ,x= 1/4
Find the zeros of 8x^2-22x+5=0
The zeros of 8x^2-22x+5=0 are x= 5/2 ,x= 1/4