What are the solutions to the equation solvefor y,x^2+2y^2=6 ?

The solutions to the equation solvefor y,x^2+2y^2=6 are y=sqrt((6-x^2)/2),y=-sqrt((6-x^2)/2)

Find the zeros of solvefor y,x^2+2y^2=6

The zeros of solvefor y,x^2+2y^2=6 are y=sqrt((6-x^2)/2),y=-sqrt((6-x^2)/2)

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solve for

y, x^{2} + 2 y^{2} = 6

y = \frac{6 - x ^{2}}{2}, y = - \frac{6 - x ^{2}}{2}

Solution steps

x^{2} + 2 y^{2} = 6

Move

x^{2}

to the right side

2 y^{2} = 6 - x^{2}

Divide both sides by

2

y^{2} = \frac{6 - x ^{2}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{6 - x ^{2}}{2}, y = - \frac{6 - x ^{2}}{2}

x^{2} = \frac{1}{4} \frac{4 3 + 1}{4}

m^{2} + m - 9 = 0

15 + (0.5) (1.06) (10)^{2} = 30 + (0.5) (1.06) v^{2}

x, x^{2} + y^{2} + z^{2} = c^{2}

s^{2} + 4 s + 29 = 0

What are the solutions to the equation solvefor y,x^2+2y^2=6 ?
The solutions to the equation solvefor y,x^2+2y^2=6 are y=sqrt((6-x^2)/2),y=-sqrt((6-x^2)/2)
Find the zeros of solvefor y,x^2+2y^2=6
The zeros of solvefor y,x^2+2y^2=6 are y=sqrt((6-x^2)/2),y=-sqrt((6-x^2)/2)