What are the solutions to the equation (3x+2)^2=81 ?

The solutions to the equation (3x+2)^2=81 are x= 7/3 ,x=-11/3

Find the zeros of (3x+2)^2=81

The zeros of (3x+2)^2=81 are x= 7/3 ,x=-11/3

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(3 x + 2)^{2} = 81

x = \frac{7}{3}, x = - \frac{11}{3}

Decimal Notation

x = 2.33333 \dots, x = - 3.66666 \dots

Solution steps

(3 x + 2)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 81 : x = \frac{7}{3}

Solve

3 x + 2 = - 81 : x = - \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{11}{3}

n^{1} + n^{2} = 4, 0 = 24

3 x^{2} - 5 x - 2 = 0

2 x^{2} - 13 x - 15 = 0

(x - 1296)^{2} = 0

3 c^{2} - 18 c + 24 = \frac{( - 2 ) - ( 2 )}{( 4 ) - ( 2 )}

What are the solutions to the equation (3x+2)^2=81 ?
The solutions to the equation (3x+2)^2=81 are x= 7/3 ,x=-11/3
Find the zeros of (3x+2)^2=81
The zeros of (3x+2)^2=81 are x= 7/3 ,x=-11/3