What are the solutions to the equation t^2+8t+1=0 ?

The solutions to the equation t^2+8t+1=0 are t=-4+sqrt(15),t=-4-sqrt(15)

Find the zeros of t^2+8t+1=0

The zeros of t^2+8t+1=0 are t=-4+sqrt(15),t=-4-sqrt(15)

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t^{2} + 8 t + 1 = 0

t = - 4 + 15, t = - 4 - 15

Decimal Notation

t = - 0.12701 \dots, t = - 7.87298 \dots

Solution steps

t^{2} + 8 t + 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 1 = 215

t_{1, 2} = \frac{- 8 \pm 2 15}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 8 + 2 15}{2 \cdot 1}, t_{2} = \frac{- 8 - 2 15}{2 \cdot 1}

t = \frac{- 8 + 2 15}{2 \cdot 1} : - 4 + 15

t = \frac{- 8 - 2 15}{2 \cdot 1} : - 4 - 15

The solutions to the quadratic equation are:

t = - 4 + 15, t = - 4 - 15

- 0.25 x^{2} + 4 x - 9 = x - 2.71

x^{2} - 2 x + 81 = 0

3 x^{2} - 5 x - 1 = 0

- 3 x^{2} - 14 x + 5 = 0

7 (x + 18)^{2} = 2800

What are the solutions to the equation t^2+8t+1=0 ?
The solutions to the equation t^2+8t+1=0 are t=-4+sqrt(15),t=-4-sqrt(15)
Find the zeros of t^2+8t+1=0
The zeros of t^2+8t+1=0 are t=-4+sqrt(15),t=-4-sqrt(15)