What are the solutions to the equation 4x(x+6)-x^2=5x^2 ?

The solutions to the equation 4x(x+6)-x^2=5x^2 are x=0,x=12

Find the zeros of 4x(x+6)-x^2=5x^2

The zeros of 4x(x+6)-x^2=5x^2 are x=0,x=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x (x + 6) - x^{2} = 5 x^{2}

x = 0, x = 12

Solution steps

4 x (x + 6) - x^{2} = 5 x^{2}

Expand

4 x (x + 6) - x^{2} : 3 x^{2} + 24 x

3 x^{2} + 24 x = 5 x^{2}

Move

5 x^{2}

to the left side

- 2 x^{2} + 24 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

2 4^{2} - 4 (- 2) \cdot 0 = 24

x_{1, 2} = \frac{- 24 \pm 24}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 24 + 24}{2 ( - 2 )}, x_{2} = \frac{- 24 - 24}{2 ( - 2 )}

x = \frac{- 24 + 24}{2 ( - 2 )} : 0

x = \frac{- 24 - 24}{2 ( - 2 )} : 12

The solutions to the quadratic equation are:

x = 0, x = 12

25 x^{2} - 100 x = 0

7 x^{2} + 41 x - 6 = 0

z, x^{2} + y^{2} + (z - 2)^{2} = 4

x, 4 y^{2} + 4 z^{2} - x^{2} - 16 = 0

- \frac{15}{4} t^{2} - 15 t + 3000 = 0

What are the solutions to the equation 4x(x+6)-x^2=5x^2 ?
The solutions to the equation 4x(x+6)-x^2=5x^2 are x=0,x=12
Find the zeros of 4x(x+6)-x^2=5x^2
The zeros of 4x(x+6)-x^2=5x^2 are x=0,x=12