What are the solutions to the equation 49n^2=9 ?

The solutions to the equation 49n^2=9 are n= 3/7 ,n=-3/7

Find the zeros of 49n^2=9

The zeros of 49n^2=9 are n= 3/7 ,n=-3/7

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49 n^{2} = 9

n = \frac{3}{7}, n = - \frac{3}{7}

Decimal Notation

n = 0.42857 \dots, n = - 0.42857 \dots

Solution steps

49 n^{2} = 9

Divide both sides by

49

n^{2} = \frac{9}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{9}{49}, n = - \frac{9}{49}

\frac{9}{49} = \frac{3}{7}

- \frac{9}{49} = - \frac{3}{7}

n = \frac{3}{7}, n = - \frac{3}{7}

x^{2} + 6 x = - 7

(5 p - 25) (p - 7) = 1 - p

25 x^{2} - 3 x - 12 = - 18 x - 12

1^{2} + 6^{2} = c^{2}

x^{2} - 2 x - 1.25 = 0

What are the solutions to the equation 49n^2=9 ?
The solutions to the equation 49n^2=9 are n= 3/7 ,n=-3/7
Find the zeros of 49n^2=9
The zeros of 49n^2=9 are n= 3/7 ,n=-3/7