What are the solutions to the equation -x^2+10x+11=0 ?

The solutions to the equation -x^2+10x+11=0 are x=-1,x=11

Find the zeros of -x^2+10x+11=0

The zeros of -x^2+10x+11=0 are x=-1,x=11

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- x^{2} + 10 x + 11 = 0

x = - 1, x = 11

Solution steps

- x^{2} + 10 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) \cdot 11}{2 ( - 1 )}

1 0^{2} - 4 (- 1) \cdot 11 = 12

x_{1, 2} = \frac{- 10 \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 12}{2 ( - 1 )}, x_{2} = \frac{- 10 - 12}{2 ( - 1 )}

x = \frac{- 10 + 12}{2 ( - 1 )} : - 1

x = \frac{- 10 - 12}{2 ( - 1 )} : 11

The solutions to the quadratic equation are:

x = - 1, x = 11

0 = - x^{2} + 4 x + 3

3 x^{2} + 2 x

y^{2} + 3 y - 7 = 0

x^{2} + 60 x + 1000 = 0

3 x^{2} - 13 x - 5 = 4 x + 1

What are the solutions to the equation -x^2+10x+11=0 ?
The solutions to the equation -x^2+10x+11=0 are x=-1,x=11
Find the zeros of -x^2+10x+11=0
The zeros of -x^2+10x+11=0 are x=-1,x=11