What are the solutions to the equation 144x^2=25 ?

The solutions to the equation 144x^2=25 are x= 5/12 ,x=-5/12

Find the zeros of 144x^2=25

The zeros of 144x^2=25 are x= 5/12 ,x=-5/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

144 x^{2} = 25

x = \frac{5}{12}, x = - \frac{5}{12}

Decimal Notation

x = 0.41666 \dots, x = - 0.41666 \dots

Solution steps

144 x^{2} = 25

Divide both sides by

144

x^{2} = \frac{25}{144}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{144}, x = - \frac{25}{144}

\frac{25}{144} = \frac{5}{12}

- \frac{25}{144} = - \frac{5}{12}

x = \frac{5}{12}, x = - \frac{5}{12}

x, y^{2} + 4 x^{2} = 0

a, a^{2} = b^{2} + c^{2} + 2 c n

- 3 x^{2} + 5 x + 9 = 0

x^{2} - 2 x - 6 = 9

a, a^{2} + 2 ab + b^{2} = 0

What are the solutions to the equation 144x^2=25 ?
The solutions to the equation 144x^2=25 are x= 5/12 ,x=-5/12
Find the zeros of 144x^2=25
The zeros of 144x^2=25 are x= 5/12 ,x=-5/12