What are the solutions to the equation 4u^2-6u+9=0 ?

The solutions to the equation 4u^2-6u+9=0 are u= 3/4+i(3sqrt(3))/4 ,u= 3/4-i(3sqrt(3))/4

Find the zeros of 4u^2-6u+9=0

The zeros of 4u^2-6u+9=0 are u= 3/4+i(3sqrt(3))/4 ,u= 3/4-i(3sqrt(3))/4

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4 u^{2} - 6 u + 9 = 0

u = \frac{3}{4} + i \frac{3 3}{4}, u = \frac{3}{4} - i \frac{3 3}{4}

Solution steps

4 u^{2} - 6 u + 9 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 9 : 63 i

u_{1, 2} = \frac{- ( - 6 ) \pm 6 3 i}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 4}, u_{2} = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 4}

u = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 4} : \frac{3}{4} + i \frac{3 3}{4}

u = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 4} : \frac{3}{4} - i \frac{3 3}{4}

The solutions to the quadratic equation are:

u = \frac{3}{4} + i \frac{3 3}{4}, u = \frac{3}{4} - i \frac{3 3}{4}

x^{3} - 6 x^{2} + 9 x + 3 x - 8 = x^{3} - 8

\frac{11}{5} x^{2} = 0

(x + 1)^{2} - 3 x = 3

(x - 7) (x - 3) + 10 x = 30

(x - 2)^{2} - 64 = 0

What are the solutions to the equation 4u^2-6u+9=0 ?
The solutions to the equation 4u^2-6u+9=0 are u= 3/4+i(3sqrt(3))/4 ,u= 3/4-i(3sqrt(3))/4
Find the zeros of 4u^2-6u+9=0
The zeros of 4u^2-6u+9=0 are u= 3/4+i(3sqrt(3))/4 ,u= 3/4-i(3sqrt(3))/4