What are the solutions to the equation (3-4x)(x+3)=9 ?

The solutions to the equation (3-4x)(x+3)=9 are x=-9/4 ,x=0

Find the zeros of (3-4x)(x+3)=9

The zeros of (3-4x)(x+3)=9 are x=-9/4 ,x=0

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(3 - 4 x) (x + 3) = 9

x = - \frac{9}{4}, x = 0

Decimal Notation

x = - 2.25, x = 0

Solution steps

(3 - 4 x) (x + 3) = 9

Expand

(3 - 4 x) (x + 3) : - 4 x^{2} - 9 x + 9

- 4 x^{2} - 9 x + 9 = 9

Move

9

to the left side

- 4 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

(- 9)^{2} - 4 (- 4) \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 ( - 4 )}, x_{2} = \frac{- ( - 9 ) - 9}{2 ( - 4 )}

x = \frac{- ( - 9 ) + 9}{2 ( - 4 )} : - \frac{9}{4}

x = \frac{- ( - 9 ) - 9}{2 ( - 4 )} : 0

The solutions to the quadratic equation are:

x = - \frac{9}{4}, x = 0

- x^{2} + 2 x + 48 = 0

x (x - 3) - 2 (x - 3) = 6

2 (w - 2) (w + 1) - (w + 3) = 0

5000 x^{2} + 5000 x - 9254.27 = 0

6 x^{2} + x - 12 = 0

What are the solutions to the equation (3-4x)(x+3)=9 ?
The solutions to the equation (3-4x)(x+3)=9 are x=-9/4 ,x=0
Find the zeros of (3-4x)(x+3)=9
The zeros of (3-4x)(x+3)=9 are x=-9/4 ,x=0