What are the solutions to the equation 3x^2-2x-15=0 ?

The solutions to the equation 3x^2-2x-15=0 are x=(1+sqrt(46))/3 ,x=(1-sqrt(46))/3

Find the zeros of 3x^2-2x-15=0

The zeros of 3x^2-2x-15=0 are x=(1+sqrt(46))/3 ,x=(1-sqrt(46))/3

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3 x^{2} - 2 x - 15 = 0

x = \frac{1 + 46}{3}, x = \frac{1 - 46}{3}

Decimal Notation

x = 2.59410 \dots, x = - 1.92744 \dots

Solution steps

3 x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 15) = 246

x_{1, 2} = \frac{- ( - 2 ) \pm 2 46}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 46}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 46}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 46}{2 \cdot 3} : \frac{1 + 46}{3}

x = \frac{- ( - 2 ) - 2 46}{2 \cdot 3} : \frac{1 - 46}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 46}{3}, x = \frac{1 - 46}{3}

n (x) = 3 x^{2} - 18 x + 23

(5 k + 7) x^{2} + 5 (k + 2) x + 3 k + 5 = 0

4 x^{2} - x - 8

(x + 6) (x - 1) = - 10

(7 x + 4)^{2} = 81

What are the solutions to the equation 3x^2-2x-15=0 ?
The solutions to the equation 3x^2-2x-15=0 are x=(1+sqrt(46))/3 ,x=(1-sqrt(46))/3
Find the zeros of 3x^2-2x-15=0
The zeros of 3x^2-2x-15=0 are x=(1+sqrt(46))/3 ,x=(1-sqrt(46))/3