What are the solutions to the equation 4(x+5)^2+6=54 ?

The solutions to the equation 4(x+5)^2+6=54 are x=2sqrt(3)-5,x=-2sqrt(3)-5

Find the zeros of 4(x+5)^2+6=54

The zeros of 4(x+5)^2+6=54 are x=2sqrt(3)-5,x=-2sqrt(3)-5

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4 (x + 5)^{2} + 6 = 54

x = 23 - 5, x = - 23 - 5

Decimal Notation

x = - 1.53589 \dots, x = - 8.46410 \dots

Solution steps

4 (x + 5)^{2} + 6 = 54

Move

6

to the right side

4 (x + 5)^{2} = 48

Divide both sides by

4

(x + 5)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 12 : x = 23 - 5

Solve

x + 5 = - 12 : x = - 23 - 5

The solutions to the quadratic equation are:

x = 23 - 5, x = - 23 - 5

- 4 x^{2} - 4 x = 0

x (x - 3) = 7

(2 x + 5)^{2} = 169

x, x^{2} + 3 x + 1 = 0

11 x^{2} - 47 x + 12 = 0

What are the solutions to the equation 4(x+5)^2+6=54 ?
The solutions to the equation 4(x+5)^2+6=54 are x=2sqrt(3)-5,x=-2sqrt(3)-5
Find the zeros of 4(x+5)^2+6=54
The zeros of 4(x+5)^2+6=54 are x=2sqrt(3)-5,x=-2sqrt(3)-5