What are the solutions to the equation (x^2)/3+2x=x ?

The solutions to the equation (x^2)/3+2x=x are x=0,x=-3

Find the zeros of (x^2)/3+2x=x

The zeros of (x^2)/3+2x=x are x=0,x=-3

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\frac{x ^{2}}{3} + 2 x = x

x = 0, x = - 3

Solution steps

\frac{x ^{2}}{3} + 2 x = x

Multiply both sides by

3

x^{2} + 6 x = 3 x

Move

3 x

to the left side

x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 1}, x_{2} = \frac{- 3 - 3}{2 \cdot 1}

x = \frac{- 3 + 3}{2 \cdot 1} : 0

x = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

x^{2} + 20 x - 45 = (x - 4)^{2} - (x - 4)^{2}

9 m^{2} - 6 m + 1 = 0

w^{2} + 375 - 376 = 0

2 t^{2} - 9 t + 4 = 0

3 x^{2} + 27 x + 24 = 0

What are the solutions to the equation (x^2)/3+2x=x ?
The solutions to the equation (x^2)/3+2x=x are x=0,x=-3
Find the zeros of (x^2)/3+2x=x
The zeros of (x^2)/3+2x=x are x=0,x=-3