What are the solutions to the equation x^2+2x=(-3)/2 ?

The solutions to the equation x^2+2x=(-3)/2 are x=-1+i(sqrt(2))/2 ,x=-1-i(sqrt(2))/2

Find the zeros of x^2+2x=(-3)/2

The zeros of x^2+2x=(-3)/2 are x=-1+i(sqrt(2))/2 ,x=-1-i(sqrt(2))/2

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x^{2} + 2 x = \frac{- 3}{2}

x = - 1 + i \frac{2}{2}, x = - 1 - i \frac{2}{2}

Solution steps

x^{2} + 2 x = \frac{- 3}{2}

Multiply both sides by

2

2 x^{2} + 4 x = - 3

Move

3

to the left side

2 x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

Simplify

4^{2} - 4 \cdot 2 \cdot 3 : 22 i

x_{1, 2} = \frac{- 4 \pm 2 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 2 2 i}{2 \cdot 2}, x_{2} = \frac{- 4 - 2 2 i}{2 \cdot 2}

x = \frac{- 4 + 2 2 i}{2 \cdot 2} : - 1 + i \frac{2}{2}

x = \frac{- 4 - 2 2 i}{2 \cdot 2} : - 1 - i \frac{2}{2}

The solutions to the quadratic equation are:

x = - 1 + i \frac{2}{2}, x = - 1 - i \frac{2}{2}

8 x^{2} = 8 x

x, x^{2} + 3 x + 3 = 0

0 = 3 + 2 x - x^{2}

25 (x - 1)^{2} - 10 (x - 1) + 1 = 0

(7 x) (x + 7) = 0

What are the solutions to the equation x^2+2x=(-3)/2 ?
The solutions to the equation x^2+2x=(-3)/2 are x=-1+i(sqrt(2))/2 ,x=-1-i(sqrt(2))/2
Find the zeros of x^2+2x=(-3)/2
The zeros of x^2+2x=(-3)/2 are x=-1+i(sqrt(2))/2 ,x=-1-i(sqrt(2))/2