What are the solutions to the equation 3t^2+6t=6 ?

The solutions to the equation 3t^2+6t=6 are t=-1+sqrt(3),t=-1-sqrt(3)

Find the zeros of 3t^2+6t=6

The zeros of 3t^2+6t=6 are t=-1+sqrt(3),t=-1-sqrt(3)

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3 t^{2} + 6 t = 6

t = - 1 + 3, t = - 1 - 3

Decimal Notation

t = 0.73205 \dots, t = - 2.73205 \dots

Solution steps

3 t^{2} + 6 t = 6

Move

6

to the left side

3 t^{2} + 6 t - 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 6) = 63

t_{1, 2} = \frac{- 6 \pm 6 3}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 6 + 6 3}{2 \cdot 3}, t_{2} = \frac{- 6 - 6 3}{2 \cdot 3}

t = \frac{- 6 + 6 3}{2 \cdot 3} : - 1 + 3

t = \frac{- 6 - 6 3}{2 \cdot 3} : - 1 - 3

The solutions to the quadratic equation are:

t = - 1 + 3, t = - 1 - 3

7 = 0.003 x^{2} + 0.001 x

x^{2} - 0.9 x - 1.52 = 0

3 X^{2} - 3 = 0

x, f (x + 2 - 2) = 2 (x + 2)^{2} - 3 (x + 2) - 1

x, y^{2} = - 4 p x^{2}

What are the solutions to the equation 3t^2+6t=6 ?
The solutions to the equation 3t^2+6t=6 are t=-1+sqrt(3),t=-1-sqrt(3)
Find the zeros of 3t^2+6t=6
The zeros of 3t^2+6t=6 are t=-1+sqrt(3),t=-1-sqrt(3)