What are the solutions to the equation x^3-7x+6=x^3+5x^2-2x-24 ?

The solutions to the equation x^3-7x+6=x^3+5x^2-2x-24 are x=2,x=-3

Find the zeros of x^3-7x+6=x^3+5x^2-2x-24

The zeros of x^3-7x+6=x^3+5x^2-2x-24 are x=2,x=-3

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x^{3} - 7 x + 6 = x^{3} + 5 x^{2} - 2 x - 24

x = 2, x = - 3

Solution steps

x^{3} - 7 x + 6 = x^{3} + 5 x^{2} - 2 x - 24

Switch sides

x^{3} + 5 x^{2} - 2 x - 24 = x^{3} - 7 x + 6

Move

6

to the left side

x^{3} + 5 x^{2} - 2 x - 30 = x^{3} - 7 x

Move

7 x

to the left side

x^{3} + 5 x^{2} + 5 x - 30 = x^{3}

Move

x^{3}

to the left side

5 x^{2} + 5 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 ( - 30 )}{2 \cdot 5}

5^{2} - 4 \cdot 5 (- 30) = 25

x_{1, 2} = \frac{- 5 \pm 25}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 5 + 25}{2 \cdot 5}, x_{2} = \frac{- 5 - 25}{2 \cdot 5}

x = \frac{- 5 + 25}{2 \cdot 5} : 2

x = \frac{- 5 - 25}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

(43 t - 16 t^{2}) - 22

2 (5 x - 3) = 24

- y = 2

4 x y - 2 y

\frac{p + 8}{- 2} = 10

What are the solutions to the equation x^3-7x+6=x^3+5x^2-2x-24 ?
The solutions to the equation x^3-7x+6=x^3+5x^2-2x-24 are x=2,x=-3
Find the zeros of x^3-7x+6=x^3+5x^2-2x-24
The zeros of x^3-7x+6=x^3+5x^2-2x-24 are x=2,x=-3