What are the solutions to the equation -8r^2=-512 ?

The solutions to the equation -8r^2=-512 are r=8,r=-8

Find the zeros of -8r^2=-512

The zeros of -8r^2=-512 are r=8,r=-8

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- 8 r^{2} = - 512

r = 8, r = - 8

Solution steps

- 8 r^{2} = - 512

Divide both sides by

- 8

r^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 64, r = - 64

64 = 8

- 64 = - 8

r = 8, r = - 8

(z + 8)^{2} = - 4

x, a (1 - \frac{x}{k}) x - b x y = 0

x^{2} - 16 + 64 = 0

12 x^{2} + 2 x = 0

0 = 4 x^{2} + 6 x + 2

What are the solutions to the equation -8r^2=-512 ?
The solutions to the equation -8r^2=-512 are r=8,r=-8
Find the zeros of -8r^2=-512
The zeros of -8r^2=-512 are r=8,r=-8