What are the solutions to the equation 7x^2-8x^2-21x+24=0 ?

The solutions to the equation 7x^2-8x^2-21x+24=0 are x=-(21+sqrt(537))/2 ,x=(sqrt(537)-21)/2

Find the zeros of 7x^2-8x^2-21x+24=0

The zeros of 7x^2-8x^2-21x+24=0 are x=-(21+sqrt(537))/2 ,x=(sqrt(537)-21)/2

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7 x^{2} - 8 x^{2} - 21 x + 24 = 0

x = - \frac{21 + 537}{2}, x = \frac{537 - 21}{2}

Decimal Notation

x = - 22.08663 \dots, x = 1.08663 \dots

Solution steps

7 x^{2} - 8 x^{2} - 21 x + 24 = 0

Refine

- x^{2} - 21 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 ( - 1 ) \cdot 24}{2 ( - 1 )}

(- 21)^{2} - 4 (- 1) \cdot 24 = 537

x_{1, 2} = \frac{- ( - 21 ) \pm 537}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 537}{2 ( - 1 )}, x_{2} = \frac{- ( - 21 ) - 537}{2 ( - 1 )}

x = \frac{- ( - 21 ) + 537}{2 ( - 1 )} : - \frac{21 + 537}{2}

x = \frac{- ( - 21 ) - 537}{2 ( - 1 )} : \frac{537 - 21}{2}

The solutions to the quadratic equation are:

x = - \frac{21 + 537}{2}, x = \frac{537 - 21}{2}

4.5 x^{2} + 32 x = 940

11600 = \frac{n}{2} (200 + (n - 1) 20)

(x + 1) (x - 2) = 10

(x + 2)^{2} + x = 2 (3 x + 5)

(x + 1) (x + 2) + 2 = 0

What are the solutions to the equation 7x^2-8x^2-21x+24=0 ?
The solutions to the equation 7x^2-8x^2-21x+24=0 are x=-(21+sqrt(537))/2 ,x=(sqrt(537)-21)/2
Find the zeros of 7x^2-8x^2-21x+24=0
The zeros of 7x^2-8x^2-21x+24=0 are x=-(21+sqrt(537))/2 ,x=(sqrt(537)-21)/2