What are the solutions to the equation x^2-x-e=0 ?

The solutions to the equation x^2-x-e=0 are x=(1+sqrt(1+4e))/2 ,x=(1-sqrt(1+4e))/2

Find the zeros of x^2-x-e=0

The zeros of x^2-x-e=0 are x=(1+sqrt(1+4e))/2 ,x=(1-sqrt(1+4e))/2

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x^{2} - x - e = 0

x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

Decimal Notation

x = 2.22287 \dots, x = - 1.22287 \dots

Solution steps

x^{2} - x - e = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - e )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- e) = 1 + 4 e

x_{1, 2} = \frac{- ( - 1 ) \pm 1 + 4 e}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1 + 4 e}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1 + 4 e}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1 + 4 e}{2 \cdot 1} : \frac{1 + 1 + 4 e}{2}

x = \frac{- ( - 1 ) - 1 + 4 e}{2 \cdot 1} : \frac{1 - 1 + 4 e}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

m^{2} + 6 m + 6 = 0

1 + x + \frac{1}{3} x^{2} = 0

3 xx + x - 26 = 0

0.000000132 (0.0000115 - x) = x^{2}

9 x^{2} - 400 = 0

What are the solutions to the equation x^2-x-e=0 ?
The solutions to the equation x^2-x-e=0 are x=(1+sqrt(1+4e))/2 ,x=(1-sqrt(1+4e))/2
Find the zeros of x^2-x-e=0
The zeros of x^2-x-e=0 are x=(1+sqrt(1+4e))/2 ,x=(1-sqrt(1+4e))/2