What are the solutions to the equation y^2+y-8=0 ?

The solutions to the equation y^2+y-8=0 are y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2

Find the zeros of y^2+y-8=0

The zeros of y^2+y-8=0 are y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + y - 8 = 0

y = \frac{- 1 + 33}{2}, y = \frac{- 1 - 33}{2}

Decimal Notation

y = 2.37228 \dots, y = - 3.37228 \dots

Solution steps

y^{2} + y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 8) = 33

y_{1, 2} = \frac{- 1 \pm 33}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 1 + 33}{2 \cdot 1}, y_{2} = \frac{- 1 - 33}{2 \cdot 1}

y = \frac{- 1 + 33}{2 \cdot 1} : \frac{- 1 + 33}{2}

y = \frac{- 1 - 33}{2 \cdot 1} : \frac{- 1 - 33}{2}

The solutions to the quadratic equation are:

y = \frac{- 1 + 33}{2}, y = \frac{- 1 - 33}{2}

x, (z - 4)^{2} = 4 x^{2} + 4 y^{2}

D = \frac{n ( n - 3 )}{2}

x^{2} - 76 x + 1080 = 0

d^{2} = 21

- 8 x^{2} = 392

What are the solutions to the equation y^2+y-8=0 ?
The solutions to the equation y^2+y-8=0 are y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2
Find the zeros of y^2+y-8=0
The zeros of y^2+y-8=0 are y=(-1+sqrt(33))/2 ,y=(-1-sqrt(33))/2